个人见解 too

,仅供参考.
[quote]原帖由
ccidnetcom 于 2008-6-19 16:24 发表

个人见解,仅供参考.
Calculations may give a 0 value for derivative coupling between two different spins?
不同自旋态之间的耦合系数应该有等于0的情况,但是我们主要计算关键电子和轨道之间的作用,所以耦合系数一般不为0,具体你可以参考这篇文献:
http://g.zhubajie.com/urllink.php?id=2580504uybdea2e5drxrohr
I guess he used SOC to replace derivative coupling for Landau-Zener formula???
应该不是吧,文献中已经明确提到了室温下的跃迁几率为13.4%.况且直接以SOC的大小衡量Landau-Zener的几率大小也是不准确的,见参考文献:
http://g.zhubajie.com/urllink.php?id=258050709l1ag5qz1cb12op
http://g.zhubajie.com/urllink.php?id=2580534wyz21qux5pz1f5fe
From the molpro 2006 manual, when we locate MECP between differentspin, we don't need to calculate derivative coupling (DC). "skip the DCevaluation if the conical intersection involves states with differentspin (e.g., a Singlet/Triplet crossing) because the coupling is thenzero." Interestingly, Shaik exactly used SOC to appromixate DC in LZ equation.
What's F paper in 2000?
F, fluoride atom.
D. G. Fedorov and M. S. Gordon, J. Chem. Phys. 112, 5611 ~2000!.
How they get velocity of the motion? Amazing!?!?
CASSCF的CONICAL关键词好象可以计算得到,我没算过
It should be wrong. CONICAL关键词 calculates DC and 2 Gradients (to get gradient difference) only. People need velocity of trajectory when it crosses. Shaik guessed velocity by "the sum of translational energies of the two reactants at 300 K". Interestingly.